25=0.0125x^2-x

Solution for 25=0.0125x^2-x equation:

25=0.0125x^2-x

We move all terms to the left:

25-(0.0125x^2-x)=0

We get rid of parentheses

-0.0125x^2+x+25=0

a = -0.0125; b = 1; c = +25;
Δ = b2-4ac
Δ = 12-4·(-0.0125)·25
Δ = 2.25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{2.25}}{2*-0.0125}=\frac{-1-\sqrt{2.25}}{-0.025}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{2.25}}{2*-0.0125}=\frac{-1+\sqrt{2.25}}{-0.025}
$